I need to get current active url in the browser and extract model from it. Is that possible?
Please Help
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Diese Frage wurde gekennzeichnet
In Python
from openerp import http
print http.request.env['ir.config_parameter'].get_param('web.base.url') # BASE URL
print http.request.httprequest
print http.request.httprequest.full_path
In Javascript
window.location.href
In js, it will return the previous menu item url, In Python it does not return full url.
I need a menu id from current url.
from openerp.http import request
print request.httprequest.url_root
Or:
base_url = self.env['ir.config_parameter'].get_param('web.base.url')
from odoo.http import request
check out/print:
request.httprequest.url
request.httprequest.base_url
request.httprequest.host_url
Hello Tessnim
you can try
1 .
from openerp.http import request
print(request.httprequest.__dict__)
or
2. refer link
\ https://www.odoo.com/forum/help-1/question/how-to-get-url-of-current-page-29394
Thanx.
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